Indian Army GD Mathematics Online Test – Level 2

Q1. Area of a rectangular ground is 12500 m². Its length is 125 m. its perimeter is?
एक आयताकार मैदान का क्षेत्रफल 12500 m² है, इसकी लम्बाई 125 m है, तो इसकी परिधि क्या होगी?

1. 450 m/मी.
2. 100 m/मी.
3. 900 m/मी.
4. 1250 m/मी.
5. Answer is: 450 m/मी.

1. Solution with Explanation
2. Area of Rectangle = Length * Breadth
   12500 = 125 * Breadth
   Breadth = 12500/125
   = 100 m
   Perimeter = 2(length + Breadth)
   = 2(125 + 100)
   = 2(225)
   =450 m

Q2. If 10, 20, x and 40 are in a proportion, the value of x will be
यदि 10, 20, X और 40 एक अनुपात में हैं तो X का मान क्या होगा ?

1. 5
2. 20
3. 30
4. 80
5. Answer is: 20

1. Solution with Explanation
2. Product of mean = Product of Extremes
   10*40 = 20 * X
   (10*40)/20 = X
   400/20 = X
   20 = X

Q3. If 10th January 2004 is Tuesday, what will be the day on 10th January 2005?
यदि 10th जनवरी 2004 को मंगलवार है, तो 10th जनवरी 2005 को कौन सा दिन होगा?

1. Wednesday
2. Thursday
3. Tuesday
4. Friday
5. Answer is: Thursday

1. Solution with Explanation
2. Thursday

Q4. A cyclist covers 12 km in an hour. What is his speed in meters per minute?
एक साइकिल सवार एक घंटे में 12 किलोमीटर तय करता है. उसकी गति मीटर प्रति मिनट में ज्ञात कीजिये.

1. 60/1000 m/s मी/सें
2. 3600/1000 m/s मी/सें
3. 200m/min मी/मि
4. 1000/60 m/s मी/सें
5. Answer is: 200 m/s मी/सें

1. Solution with Explanation
2. Speed = Distance/ Time
   12 km = 1 hour
   12 km = 12000 m
   1 hour = 60 Minutes
   Speed = 12000/60
   = 200m/minute

Q5. The cost of 18 bananas at the rate of Rs 4 per dozen will be
4 रु. प्रति दर्जन के अनुसार 18 केलों का मूल्य क्या होगा?

1. 5
2. 6
3. 7
4. 8
5. Answer is: 6

1. Solution with Explanation
2. The cost of 12 Bananas = Rs 4
   The cost of 18 Bananas = (18*4)/12
   = Rs 6

Q6. 12 men or 18 women can reap a field in 7 days, 4 men and 8 women can reap the same field in
12 पुरुष या 18 महिलाएं एक खेत की कटाई 7 दिन में करते हैं, तो उसी खेत की कटाई 4 पुरुष और 8 महिलाएं कितने दिन में करेंगे?

1. 3 days/दिन
2. 6 days/दिन
3. 9 days/दिन
4. 10 days/दिन
5. Answer is: 9 days/दिन

1. Solution with Explanation
2. 12 men can do the work in 7 days.So, 1 man can do the task in 12 x 7 = 84So, part of total work completed in one day by a man = 1/84Work completed by 4 men in one day = 4/84 = 1/21 = 3/6318 women can do the same task oin 7 days.

   So, one woman can do task in 18 x 7 = 126

   So, part of total work completed in one day by an woman = 1/126

   Work completed by 8 women in 1 day= 8/126 = 4/63.

   Therefore, fraction of work completed in one day by 4 men and 8 women, = 3/63 + 4/63 = 7/63 = 1/9.

   So work is completed by 4 men and 8 women in 9 days.

Q7. The average of the height of 5 students having height 30, 40, 50, 60, 70 will be?
5 विद्यार्थी जिनकी ऊंचाई क्रमशः 30, 40, 50, 60, 70 है उनकी औसत ऊंचाई क्या होगी ?

1. 40
2. 45
3. 50
4. 55
5. Answer is: 50

1. Solution with Explanation
2. Average = sum of observations/ number of observations
   Average = 30+40+50+60+70/5
   = 250/5
   = 50

Q8. At what rate percent per annum will a sum of money double in 8 years?
किस प्रति वर्ष ब्याज दर पर कोई राशि 8 साल में दुगनी हो जाएगी?

1. 12.5%
2. 20%
3. 25%
4. 13%
5. Answer is: 12.5%

1. Solution with Explanation
2. Let principal = P,
   Then, S.I.= P
   Time=8 years
   Rate = [(100 x P)/ (P x 8)]%
   12.5% per annum.

Q9. A man buys a toy for Rs 1000 and sells it for Rs 1500. His gain percent is
एक व्यक्ति एक खिलौना 1000 रुपए में ख़रीदता है और 1500 रुपए में बेच देता है, तो उसे कितने प्रतिशत का फायदा हुआ?

1. 33.5%
2. 25%
3. 50%
4. 40%
5. Answer is: 50%

1. Solution with Explanation
2. Gain percent = (Gain/Cost Price)*100
   = (500/1000)*100
   = 50%

Q10. 3 hrs and 45 minutes = ____________ seconds ?
3 घंटे और 45 मिनट्स = ____________ सेकेंड्स ?

1. 13500
2. 13000
3. 18000
4. 10500
5. Answer is: 13500

1. Solution with Explanation
2. 3 Hours = 3*60*60 seconds
   = 10800
   45 minutes = 45*60
   = 2700 seconds
   3 hours 45 minutes = 10800 + 2700 =
   = 13500

Q11. 30% of 140 = x% of 840, then x is
140 का 30% = 840 का x% है, तो x क्या होगा ?

1. 5
2. 6
3. 10
4. 15
5. Answer is: 6

1. Solution with Explanation
2. 30/100 * 140 = x/100 * 840
   x = 5

Q12. Which one of the following is equivalent of 6/20 ?
निम्न में से कौन सा 6/20 के बराबर है?

1. 6%
2. 20%
3. 26%
4. 30%
5. Answer is: 30%

1. Solution with Explanation
2. 30%
   As, 30/100 = (30*2)/(100*2)
   = 6/20

Q13. The square root of 4096 is
4096 किसका वर्गमूल है?

1. 24
2. 33
3. 64
4. 96
5. Answer is: 64

1. Solution with Explanation
2. 2*2*2*2*2*2*2*2*2*2*2*2
   2*2*2*2*2*2
   64

Q14. LCM of (2x3x5) and (3x5x7) is equal to
(2x3x5) और (3x5x7) का ल.स.म. किसके बराबर है ?

1. 3
2. 3×5
3. 2x3x5x7
4. 2x3x5x3x5x7
5. Answer is: 2x3x5x7

1. Solution with Explanation
2. Taking 3*5
   2*3*5*7

Q15. A cricket player scores 85 runs in his 17th innings, with this his overall average increases by 3. what is his average after 17th innings?
एक क्रिकेट खिलाडी अपनी 17वीं इन्निंग्स में 85 रन मार कर अपने कुल्ल औशद को 3 से बढ़ा देता है. 17वीं इन्निंग्स के बाद उसका कुल्ल औशद कितना होगा?

1. 37
2. 38
3. 36
4. 35
5. Answer is: 37

1. Solution with Explanation
2. Let the average after 17th innings = xThen average after 16th innings = (x−3)(x−3)Therefore 16(x−3)+85=17×16(x−3)+85=17xTherefore x=37

Q16. Brass contains copper and zinc in the ratio of 11:6 respectively.
In what amount is zinc present in 850kg of brass?
अगर पीतल में ताम्बे और जस्ते का अनुपात 11:6 है तो 850 kg पीतल में कितना जस्ता होगा?

1. 420kg
2. 510kg
3. 550 kg
4. 300kg
5. Answer is: 300kg

1. Solution with Explanation
2. Let the quantity of copper = 11x
   Let the quantity of zinc = 6x
   According to the question ;
   11x + 6x = 850
   17x = 850
   x= 50
   The amount of Zinc = 6*50 = 300 kg

Q17. Ramu gets Rs.10285 after 10% increment in salary. Determine his original income.
रामू के वेतन में 10% वृद्धि होने के बाद उसकी सैलरी 10285 रु. होगयी. उसकी वर्तमान सैलरी ज्ञात कीजिए.

1. 9350
2. 9000
3. 9530
4. 9200
5. Answer is: 9350

1. Solution with Explanation
2. Let the originial income of Ramu be x
   After increment of 10% , the salary become 11x/10
   11x/10 = 10285
   x = 9350

Q18. If CP=685 and SP=794.60, then what is gain or loss percent?
अगर CP=685 और SP=794.60 है, तो लाभ प्रतिशत या हनी प्रतिशत क्या होगा?

1. loss 16%
2. gain 10%
3. gain 16%
4. loss 6%
5. Answer is: gain 16%

1. Solution with Explanation
2. Gain = Selling Price – Cost Price
   = 794.60-685
   = 109.6
   Gain percent = (Gain/cost price) * 100
   = (109.6/685) * 100
   = 16%
   Gain percent = 16%

Q19. A 90 M long train crosses a tunnel in 21 seconds with the speed of 48 Km/hr. What is the length of the tunnel?
एक 90 M लम्बी रेल गाड़ी 48 km/hr की गति से एक सुरंग को 21 सेकंड में पर करती है, तो उस सुरंग की लम्बाई कितनी होगी ?

1. 190 M
2. 180 M
3. 280 M
4. 290 M
5. Answer is: 190 M

1. Solution with Explanation
2. Speed = 48km/hr = 48*5/18
   According to the question
   48*5/18 = (90+x)/21
   35*8 = 90+x
   x = 190

Q20. The area of a square field is 12.96 cm². What will be the length of wire to fence the field?
एक चौकोर का छेत्रफल 12.96 cm² है, उस चौकोर की बाढ़ लगाने में इस्तेमाल की जाने वाली तार की लंम्बाई कितनी होगि?

1. 12.4 cm
2. 10.4 cm
3. 14.4 cm
4. none of the above
5. Answer is: 14.4 cm

1. Solution with Explanation
2. The area of square field = 12.96 cm² = side*side
   The length of each side = √12.96 = 3.6 cm
   The length of the wire to fence the field( Perimeter) = 4*3.6 = 14.4 cm

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